2x^2+15x-6.9=0

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Solution for 2x^2+15x-6.9=0 equation:



2x^2+15x-6.9=0
a = 2; b = 15; c = -6.9;
Δ = b2-4ac
Δ = 152-4·2·(-6.9)
Δ = 280.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{280.2}}{2*2}=\frac{-15-\sqrt{280.2}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{280.2}}{2*2}=\frac{-15+\sqrt{280.2}}{4} $

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